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Jul 1, 2013 at 20:42 comment added Theo Johnson-Freyd Ah, great. I probably knew that at some point.
Jul 1, 2013 at 18:40 comment added Qiaochu Yuan @Theo: a map is an epimorphism if and only if its cokernel pair (ncatlab.org/nlab/show/cokernel+pair) is trivial, which is a type of pushout. But yes, I also noticed later that you don't need that fact to show that $\mathbb{F}_p \to \emptyset$.
Jul 1, 2013 at 17:59 comment added Theo Johnson-Freyd Then again, you only use "preserves epimorphisms" to show that $\mathbb F_p \mapsto \emptyset$, and this can be seen because the two inclusions $\mathbb F_p \to \mathbb F_p \otimes \mathbb F_p$ are isomorphisms.
Jul 1, 2013 at 17:58 comment added Theo Johnson-Freyd I do like that your examples don't need* the cosheaf to be cocontinuous, but just to distribute over finite coproducts. (*Except for the question in my previous comment?)
Jul 1, 2013 at 17:55 comment added Theo Johnson-Freyd Awesome. I should have thought of the $\mathrm{Vect}$ case. In Edit 2, maybe I'm being dumb, but why must a cosheaf preserve epimorphisms? Not every epimorphism is split, e.g. $\mathbb Z \to \mathbb Q$ is an epi in $\mathrm{CRing}$.
Jul 1, 2013 at 15:56 vote accept Theo Johnson-Freyd
Jul 1, 2013 at 8:22 history edited Qiaochu Yuan CC BY-SA 3.0
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Jul 1, 2013 at 7:59 history edited Qiaochu Yuan CC BY-SA 3.0
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Jul 1, 2013 at 7:49 history undeleted Qiaochu Yuan
Jul 1, 2013 at 7:49 history edited Qiaochu Yuan CC BY-SA 3.0
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Jul 1, 2013 at 7:31 history deleted Qiaochu Yuan
Jul 1, 2013 at 7:28 history answered Qiaochu Yuan CC BY-SA 3.0