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Apr 20, 2017 at 10:37 history edited Joseph O'Rourke CC BY-SA 3.0
Image links broken; now fixed.
Apr 13, 2017 at 12:58 history edited CommunityBot
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Jun 29, 2013 at 13:21 vote accept Joseph O'Rourke
Jun 29, 2013 at 3:37 comment added Włodzimierz Holsztyński One may pose a related question about a finite subset of the projective plane and the arcs of the straight lines--there are just simple points, no notion of any antipodal points. The questions are essentially different but at least they are similar, and the projective version has simpler formulation I'd think (a single projective point is something of a substitute, not exactly, of an antipodal pair).
Jun 28, 2013 at 23:48 history edited Joseph O'Rourke CC BY-SA 3.0
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Jun 28, 2013 at 22:36 answer added Johan Wästlund timeline score: 4
Jun 28, 2013 at 18:03 comment added Johan Wästlund Answering my own question: When $n\geq 2$, the convex hull is spanned by at least 3 points, so we can find two of them that are adjacent and of different color, say red and green. After pairing them up, we solve the subproblem of the remaining $2n-2$ points under red-green color blindness (treating the other red and green points as having the same color).
Jun 28, 2013 at 14:41 comment added Joseph O'Rourke That's a wonderfully clarifying reformulation of the essence of the discrete geometry question at the heart of this!
Jun 28, 2013 at 14:04 comment added Johan Wästlund Is it relevant/necessary that the points are on a sphere and chords are connecting nearly antipodal points? What if there are $2n$ points in "general position" in the plane and they are colored by $n$ colors, 2 points of each color. Can we always find a perfect matching of non-crossing line segments such that a walk that alternates between following a line segment and jumping to the other point of the same color will connect the points to a single cycle?
Jun 28, 2013 at 11:48 history asked Joseph O'Rourke CC BY-SA 3.0