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Timeline for Determinants in Graph Theory

Current License: CC BY-SA 3.0

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S Sep 2, 2017 at 15:38 history suggested Peter Heinig CC BY-SA 3.0
This edit is to second the recent correction of Tyler Streeter. To give context and support, I added a relevant part of Biggs, Algebraic Graph Theory, CUP, second edition.
Sep 2, 2017 at 15:25 review Suggested edits
S Sep 2, 2017 at 15:38
S Sep 2, 2017 at 14:50 history suggested Tyler Streeter CC BY-SA 3.0
$r(G)$ definition is incorrect: it should also include $K_2$ components. See e.g. [Harary, 1962](http://yaroslavvb.com/papers/harary-determinant.pdf) eq.8, where $e_i$ (same as $r(G)$ here) is defined at the bottom of p.207 as the number of even components that are lines ($K_2$) or cycles.
Sep 2, 2017 at 12:35 review Suggested edits
S Sep 2, 2017 at 14:50
Mar 24, 2016 at 3:21 comment added Tyler Streeter I'll think about special cases where all even components are $K_2$. In any case, thanks for the quick responses, and for posting this helpful answer in the first place.
Mar 23, 2016 at 23:48 history edited Jernej CC BY-SA 3.0
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Mar 23, 2016 at 23:48 comment added Jernej @TylerStreeter Yes, you're right about the references. I am not sure at this point how I got to the presented definition of $r(H)$ and at this point its safer to just edit the post to use the number of even cycles.
Mar 23, 2016 at 22:28 comment added Tyler Streeter To rephrase my comments: in both the Biggs and Harary references, it appears that the expression involves $(-1)$ raised to the power "number of even components," not "number of $K_2$ components." So the description above appears incorrect, unless I'm missing something.
Mar 23, 2016 at 21:10 comment added Tyler Streeter Even in this specific class of graphs (i.e. spanning subgraphs of $G$ having only $K_2$ and cycles as components), I think $r(H)$ here should be (congruent to, mod 2) the number of even components, not the number of $K_2$ components. Or am I missing something?
Mar 23, 2016 at 20:25 comment added Jernej @TylerStreeter That's right r(H) has a different meaning in general (the rank of H). In this case the function is simplified since we only evaluate it for the specific class of graphs
Mar 23, 2016 at 20:20 comment added Tyler Streeter Looking at Biggs (chapter "Determinant expansions"), and also the original Harary 1962 paper referenced there, it seems that $r(H)$ represents the number of even components, not the number of $K_2$ components as you describe here. Is that correct?
S Jul 17, 2014 at 19:33 history suggested Jeroen Zuiddam CC BY-SA 3.0
There were two dots after K_2.
Jul 17, 2014 at 19:26 review Suggested edits
S Jul 17, 2014 at 19:33
Jun 27, 2013 at 10:16 history edited Jernej CC BY-SA 3.0
added 6 characters in body
Jun 27, 2013 at 9:12 history answered Jernej CC BY-SA 3.0