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Post Closed as "Not suitable for this site" by Mikael de la Salle, Yemon Choi, Benjamin Steinberg, Andy Putman, Andrey Rekalo
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user2008790
user2008790
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Suppose A is a covariance matrix whose diagonal elements are same, i.e. $A_{1,1}=A_{2,2}=\cdots=A_{N,N}$, can we conclude that A is full rank?

Thanks Suppose the absolute values of the off-diagonal elements in A are all smaller than the diagonal elements in A. Thanks!

Suppose A is a covariance matrix whose diagonal elements are same, i.e. $A_{1,1}=A_{2,2}=\cdots=A_{N,N}$, can we conclude that A is full rank?

Thanks!

Suppose A is a covariance matrix whose diagonal elements are same, i.e. $A_{1,1}=A_{2,2}=\cdots=A_{N,N}$, can we conclude that A is full rank? Suppose the absolute values of the off-diagonal elements in A are all smaller than the diagonal elements in A. Thanks!

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user2008790
user2008790
  • 3
  • 3

Rank of covariance matrix whose diagonal elements are same

Suppose A is a covariance matrix whose diagonal elements are same, i.e. $A_{1,1}=A_{2,2}=\cdots=A_{N,N}$, can we conclude that A is full rank?

Thanks!