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Jun 26, 2013 at 20:53 vote accept Michael Tinker
Jun 26, 2013 at 19:39 comment added Nate Eldredge In short, it's the fact that $e^{tH}$ is a semigroup.
Jun 26, 2013 at 19:34 history answered Otis Chodosh CC BY-SA 3.0