Timeline for Existence of a possible counterexample in automaton semigroups
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
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| Jun 28, 2013 at 17:24 | comment | added | Benjamin Steinberg | I am skeptical of such a recipe but I think I have an answer above, if correct. | |
| Jun 27, 2013 at 8:32 | history | edited | Salvo Tringali | CC BY-SA 3.0 |
Corrections
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| Jun 26, 2013 at 12:58 | comment | added | Benjamin Steinberg | Inflation doesn't work. | |
| Jun 25, 2013 at 23:19 | comment | added | Salvo Tringali | I made a mess with the table, but you are still right: The construction as it is doesn't work. Is there any hope to fix it? | |
| Jun 25, 2013 at 23:04 | comment | added | Benjamin Steinberg | e is not a new identity in your table for 1 and e. I think your general construction inflates the adjoined identity and hence e and infinity have the same rows and columns. | |
| Jun 25, 2013 at 22:52 | history | edited | Salvo Tringali | CC BY-SA 3.0 |
Added a three element example
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| Jun 25, 2013 at 17:37 | history | edited | Salvo Tringali | CC BY-SA 3.0 |
Completed a previous, incomplete answer
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| Jun 25, 2013 at 17:18 | history | edited | Salvo Tringali | CC BY-SA 3.0 |
added 65 characters in body
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| Jun 25, 2013 at 17:17 | history | rollback | Salvo Tringali |
Rollback to Revision 1
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| Jun 25, 2013 at 17:11 | history | edited | Salvo Tringali | CC BY-SA 3.0 |
added 45 characters in body
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| Jun 25, 2013 at 17:06 | history | answered | Salvo Tringali | CC BY-SA 3.0 |