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Siméon
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I think I would go for a Euler-Maclaurin expansion. of the second term of

$$ -\sum_{k=a}^N \log(e^{k\kappa}-1) = -\kappa\frac{(N+a)(N-a+1)}{2}-\sum_{k=a}^N\log(1-e^{-k\kappa}). $$

I think I would go for a Euler-Maclaurin expansion.

I think I would go for a Euler-Maclaurin expansion of the second term of

$$ -\sum_{k=a}^N \log(e^{k\kappa}-1) = -\kappa\frac{(N+a)(N-a+1)}{2}-\sum_{k=a}^N\log(1-e^{-k\kappa}). $$

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Siméon
  • 635
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I think I would go for a Euler-Maclaurin expansion.