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Jun 25, 2013 at 16:56 comment added David Collins Nope, I think I'm missing the point. It's not that it gets close together, it's that some part of it is infinitely long.
Jun 25, 2013 at 15:58 comment added David Collins No, I don't think that's quite right. I think I mean there exists $\epsilon>0$ such that for every $\delta$ with $0<\delta<\epsilon$ and for every $x\in A$, the intersection of $A$ with the $\delta$ ball around $x$ is connected.
Jun 24, 2013 at 21:59 comment added David Collins Hmm, that's a nice counterexample. What if we include a uniform bound on being connected locally, something like: there exists $\epsilon>0$ such that for all $x\in A$, the intersection of $A$ and the $\epsilon$-ball around $x$ is connected. It seems like that condition might even imply the finite volume.
Jun 22, 2013 at 6:50 history answered Nik Weaver CC BY-SA 3.0