Skip to main content
6 events
when toggle format what by license comment
Jun 25, 2013 at 3:02 review First posts
Jun 25, 2013 at 15:43
Jun 20, 2013 at 8:03 history edited Neil Strickland CC BY-SA 3.0
Spelling in title
Jun 20, 2013 at 7:48 comment added Robert Israel Diameters really have very little to do with it. Given any covering of $D$ that misses a point $p$ of $X$, and any set $S$ of diameter $d$ disjoint from $p$, you can take the unions of the members of the covering with $S$ and get a new covering whose elements all have diameter $\ge d$, but it still misses $p$.
Jun 20, 2013 at 6:30 comment added Anton Petrunin If the diameters bounded below, the cvering of D might not cover X. For example, let X be the real line. D be the set of rational numbers and it is covered by two sets $(-\infty,\sqrt{2})$ and $(\sqrt{2},+\infty)$.
Jun 20, 2013 at 6:06 comment added Zev Chonoles Crossposted from math.SE: math.stackexchange.com/q/425179/264
Jun 20, 2013 at 5:57 history asked Michael CC BY-SA 3.0