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Jun 21, 2013 at 23:01 vote accept Bo_Y
Jun 21, 2013 at 9:57 answer added diverietti timeline score: 1
Jun 20, 2013 at 6:07 comment added Bo_Y thanks for the suggestion. sorry I still can't figure it out, Say for a fixed point, those PSH functions $u_j$ may take very different values on this point, and they may grow large outside $V_j$, I did not get $\sum \epsilon_j u_j$ must converge everywhere. sorry if I made any simple misunderstanding.
Jun 20, 2013 at 5:58 history edited Bo_Y CC BY-SA 3.0
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Jun 19, 2013 at 15:48 comment added diverietti In his proof, you have just to choose the multiplying constants converging very fast to 0. For instance, $\varepsilon_j=1/(2^j(1+\max_{\partial V_j}v_0))$ will work.
Jun 19, 2013 at 5:26 history asked Bo_Y CC BY-SA 3.0