Timeline for Numbers with known finite irrationality measure greater than 2
Current License: CC BY-SA 3.0
3 events
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Jun 19, 2013 at 18:39 | comment | added | Ben Wieland | Yes, you're right, it should be $a_{n+1}=q_n^{\mu-2}$. Then $q_{n+1}\sim q_n^{\mu-1}$ and the reciprocal error is $q_{n+1}q_n\sim q_n^\mu$. | |
Jun 19, 2013 at 17:39 | comment | added | jsm | Thanks, I'm happy to specify numbers by their continued fraction expansion. But don't you mean $\mu-2$ instead of $\mu-1$? (sorry if I'm being stupid here) | |
Jun 19, 2013 at 1:55 | history | answered | Ben Wieland | CC BY-SA 3.0 |