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Apr 13, 2017 at 12:58 history edited CommunityBot
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S Jul 3, 2013 at 20:07 history bounty ended CommunityBot
S Jul 3, 2013 at 20:07 history notice removed CommunityBot
Jun 26, 2013 at 18:41 comment added Sylvain JULIEN If I'm not mistaken, Symmetric Density Conjecture would follow from Hardy-Littlewood k-Tuple conjecture as stated in mathworld.wolfram.com/k-TupleConjecture.html and the fact that $w(q,m_1,...,m_k)=w(q,-m_1,....,-m_k)$. This must be established rigorously though.
S Jun 25, 2013 at 19:00 history bounty started Sylvain JULIEN
S Jun 25, 2013 at 19:00 history notice added Sylvain JULIEN Draw attention
Jun 25, 2013 at 18:56 history edited Sylvain JULIEN CC BY-SA 3.0
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Jun 21, 2013 at 21:28 comment added Sylvain JULIEN And then one would have, thanks to Prime Number Theorem, $\sigma_{m}=1$. Hence Symmetric density conjecture alone implies $\sigma_{+}=2$.
Jun 21, 2013 at 20:52 comment added Sylvain JULIEN Read $\displaystyle{\lim_{\varepsilon\to 0}\lim_{x\to\infty}\delta_{\varepsilon,x}(\sigma)}$ in the previous comment.
Jun 21, 2013 at 20:49 comment added Sylvain JULIEN Let $\displaystyle{\delta(\sigma):=\lim_{\varepsilon\to 0}\lim_{x\to\infty}\delta_{\varepsilon,x}}$. Then Symmetric Density conjecture implies $\sigma_{m}:=\int_{\sigma_{-}}^{\sigma_{+}}\sigma\delta(\sigma)d\sigma$.
Jun 19, 2013 at 21:18 comment added Sylvain JULIEN @Charles : Indeed.
Jun 19, 2013 at 19:05 comment added Charles You don't need the twin prime conjecture to get $\sigma_-=0$; Zhang's proof of the Bounded Gap Conjecture suffices.
Jun 19, 2013 at 0:49 comment added Gerry Myerson See also previous questions about "primality radius", mathoverflow.net/questions/90120/… and mathoverflow.net/questions/130333/… and mathoverflow.net/questions/132973/… and mathoverflow.net/questions/61842/about-goldbachs-conjecture
Jun 18, 2013 at 17:47 history asked Sylvain JULIEN CC BY-SA 3.0