Thompson's group $F$ is totally ordered. See here for a description of all possible bi-orderings. Indeed, all diagram groups are totally orderable (see here). The pure braided Thompson group $BF$ also bi-orderable (see herehere).
changed http -> https and updated the dead link (the question has been bumped anyway)
Martin Sleziak
- 4.7k
- 4
- 35
- 40
Martin Sleziak
- 4.7k
- 4
- 35
- 40