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Nov 8, 2023 at 17:16 history edited Martin Sleziak
edited tags
Nov 8, 2023 at 17:07 history edited Michael Hardy CC BY-SA 4.0
added 4 characters in body
Feb 24, 2021 at 10:25 answer added robjohn timeline score: 9
Jan 3, 2021 at 9:43 answer added Fedor Petrov timeline score: 5
Jan 2, 2021 at 17:44 history edited YCor CC BY-SA 4.0
removed capitals from title (the question was bumped anyway)
Jan 1, 2021 at 1:49 answer added Fedor Petrov timeline score: 9
Aug 5, 2016 at 13:39 answer added David E Speyer timeline score: 18
Jul 13, 2013 at 6:45 vote accept RandomStudent
Jul 1, 2013 at 4:04 answer added Noam D. Elkies timeline score: 21
Jun 25, 2013 at 3:02 review First posts
Jun 25, 2013 at 13:27
S Jun 16, 2013 at 13:26 vote accept RandomStudent
Jul 13, 2013 at 6:45
Jun 16, 2013 at 13:18 vote accept RandomStudent
S Jun 16, 2013 at 13:26
Jun 14, 2013 at 14:40 answer added Noam D. Elkies timeline score: 36
Jun 14, 2013 at 13:00 comment added Johan Andersson The simplest upper bound to prove is $4^n$ (which is still stronger than your bound) and just follows from the binomial expansion of $(1+1)^{2n}$. Peter's answer gives a less wasteful estimate.
Jun 14, 2013 at 12:52 vote accept RandomStudent
Jun 16, 2013 at 13:18
Jun 14, 2013 at 12:36 answer added Péter Komjáth timeline score: 22
Jun 14, 2013 at 10:26 history asked RandomStudent CC BY-SA 3.0