Timeline for upper bound on product of distances from points on a circle
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| Jun 14, 2013 at 2:18 | comment | added | mohi | thanks this was a very useful answer is the modulus of continuity of f(θ)=log|a−e2πiθ| easy to calculate? Based on page 145 of kuipers and Niederreiter this is equal to M(h)=sup|θ2−θ1|≤h|f(θ2)−f(θ1)| for 0≤h≤1. In this case this is equal to M(h)=sup|θ2−θ1|≤hlog|a−e2πiθ2||a−e2πiθ1| | |
| Jun 14, 2013 at 2:01 | vote | accept | mohi | ||
| Jun 13, 2013 at 0:35 | history | answered | Gerry Myerson | CC BY-SA 3.0 |