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Nov 27, 2021 at 16:26 answer added Dmitry Krachun timeline score: 1
Nov 27, 2021 at 14:27 history edited José Hdz. Stgo. CC BY-SA 4.0
edited title
Oct 16, 2013 at 2:14 answer added Noam D. Elkies timeline score: 6
Oct 15, 2013 at 22:40 history edited Ricardo Andrade
added top level tag (since question was bumped to the front page)
Jun 25, 2013 at 3:02 review First posts
Jun 26, 2013 at 4:17
Jun 10, 2013 at 13:28 comment added Johan Andersson @Gerald, My answer below answers that question also. Yes, It is continuous on the open interval $(0,2\pi)$-
Jun 10, 2013 at 13:26 comment added Gerald Edgar How about a (perhaps) more delicate question. Is it continuous on open interval $(0,2\pi)$ ??
Jun 10, 2013 at 12:47 answer added Johan Andersson timeline score: 6
Jun 10, 2013 at 10:43 comment added Venkataramana If $\alpha <1/2$ then the $L^2$ norm of your function is $\sum _{n=1}^{\infty} \frac{1}{n^{2\alpha}}$, which is infinite. Hence your function is not $L^2$ and therefore not continuous.
Jun 10, 2013 at 10:12 history asked Pavel CC BY-SA 3.0