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Jun 5, 2013 at 3:33 comment added Noah Schweber I don't particularly mind, but I'm curious: why the downvote?
Jun 5, 2013 at 0:30 comment added The User Indeed, it does not matter, but I was a bit surprised about your words “no finite description” for a recursively enumerable set.
Jun 5, 2013 at 0:00 comment added Noah Schweber Okay, then take the set of (codes for) Diophantine equations with infinitely many solutions, or the set of (codes for) recursive subtrees of $\omega^{<\omega}$ which are well-founded; or the real coding the true theory of arithmetic. It really doesn't matter.
Jun 4, 2013 at 22:39 comment added The User Well, “description by an algorithm” is ambiguous. But I think we all know what we mean and agree that recursively enumerable sets are very “constructive”, but you might want to insist on recursive sets, which are even more “constructive”.
Jun 4, 2013 at 22:22 comment added François G. Dorais User, I would have agreed with you if you hadn't added the (deliberately?) ambiguous phrase "algorithmic description" since Noah's point is that this is a set that has no algorithmic decision procedure.
Jun 4, 2013 at 21:54 comment added Noah Schweber Also, that seems to be the meaning of "finite description" most consistent with the OP's question (which is, however, extremely vague).
Jun 4, 2013 at 21:53 comment added Noah Schweber I meant an algorithm; I'm just saying $Z$ is not recursive. My point is just that we can find sets with "somewhat nice" descriptions which provably have no "nice" descriptions, for almost any meanings of "somewhat nice" and "nice." :P
Jun 4, 2013 at 21:52 history edited Noah Schweber CC BY-SA 3.0
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Jun 4, 2013 at 21:50 comment added The User What do you mean by a “finite description”?$Z$ is recursively enumerable, it has a finite, algorithmic description, there are very few notions that are even more constructive.
Jun 4, 2013 at 21:43 history answered Noah Schweber CC BY-SA 3.0