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Jun 7, 2013 at 1:03 vote accept liubenyuan
Jun 5, 2013 at 9:49 history closed Chris Godsil
Benoît Kloeckner
Yemon Choi
Denis Serre
Neil Strickland
off topic
Jun 4, 2013 at 14:34 comment added Julien Note that $A=0$, $B$ any matrix with nonzero trace, is a pretty good counterexample too.
Jun 4, 2013 at 12:52 comment added liubenyuan Dear Peter, you mean that $\mathrm{Tr}(\mathbf{AB^T})$ is PD and therefore could not equal $0$ ?
Jun 4, 2013 at 12:51 history edited liubenyuan CC BY-SA 3.0
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Jun 4, 2013 at 11:55 comment added Peter Michor $\text{Tr}(AB)$ is a symmetric non-degenerate inner product on the space of all matrices, with signature $(\frac{(n+1)n}2,\frac{(n-1)n}2)$. Over $mathbb R$, the symmetric bilinear form $\text{Tr}(AB^\top)$ is positive definite.
Jun 4, 2013 at 10:57 answer added Dietrich Burde timeline score: 1
Jun 4, 2013 at 9:22 history edited liubenyuan CC BY-SA 3.0
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Jun 4, 2013 at 9:13 history edited liubenyuan CC BY-SA 3.0
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Jun 4, 2013 at 9:09 comment added liubenyuan Dear Chris, I have modified my problem. I think it related to the problem of linalg and the optimization of logdet function, this problem happened mostly in $\ell_1$ minimization solvers. L
Jun 4, 2013 at 9:05 history edited liubenyuan CC BY-SA 3.0
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Jun 4, 2013 at 8:58 history edited liubenyuan CC BY-SA 3.0
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Jun 4, 2013 at 8:56 comment added Chris Godsil This is not the right site for this question. See the FAQ for alternatives.
Jun 4, 2013 at 8:49 history asked liubenyuan CC BY-SA 3.0