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Jun 5, 2013 at 2:42 vote accept Windi
Jun 5, 2013 at 2:42
Jun 1, 2013 at 21:45 comment added GH from MO Yes, but this is not what you originally asked. Your question involved $F^{\times 2}$ as a subset of $F^\times$ (not just as an abstract group), hence the correction factor you need (in your original equation) will also depend on the index $(F^\times:F^{\times 2})$. This, on the other hand, depends on whether $2$ is a unit in the maximal compact subring of $F$ or not. Read my response.
Jun 1, 2013 at 21:11 history answered Windi CC BY-SA 3.0