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Jun 15, 2013 at 14:31 history edited XL _At_Here_There CC BY-SA 3.0
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Jun 8, 2013 at 4:53 comment added XL _At_Here_There They are not all algebraic,and in some cases they are all transcendental.
May 31, 2013 at 9:54 comment added XL _At_Here_There @S. Carnahan,and let me think about it carefully later
May 31, 2013 at 9:12 comment added XL _At_Here_There @S. Carnahan,encyclopediaofmath.org/index.php/Algebraic_function Have I misunderstood what parametrization of algebraic function is ?Or the function like $$f_1(x),\cdots,f_n(x)$$ are not algebraic?
May 31, 2013 at 5:43 comment added S. Carnahan I don't see why you should expect automorphic functions to parametrize arbitrary varieties. If you have a smooth plane curve $P(x,y)=0$ of positive genus, you cannot write $y$ as a function of $x$ without choosing branches. A standard example is $y^2 = x^3+1$, where $y=\pm \sqrt{x^3+1}$ is not really a function of $x$, and is not automorphic (as far as I know).
May 31, 2013 at 4:03 history edited XL _At_Here_There CC BY-SA 3.0
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May 31, 2013 at 3:58 history edited XL _At_Here_There CC BY-SA 3.0
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May 31, 2013 at 3:49 history edited XL _At_Here_There CC BY-SA 3.0
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May 31, 2013 at 3:42 history edited XL _At_Here_There CC BY-SA 3.0
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May 30, 2013 at 22:55 comment added XL _At_Here_There @all,and such Diophantine equations may be a system of equation,and we suppose we just ask about other variables' solutions which is a function of one variable in the equations or equation,there are two variables in Diophantine equations or more,three variables is also just a special case .it is irrelevent whether such Diophantine equations have integer as solution or not.
May 30, 2013 at 22:44 comment added XL _At_Here_There @quim,@François,@Charles,@ Dietrich ,we just suppose other variables can have a function of x ,and the functions satisify the Diophantine equations,I do not know what functions they are,some of them may be rational ,lik the example,some of them may be algebraic ,whether implicit or explicit,is it possible that some of them transcendental?.Dietrich,I am not asking about parametrization of solution,I know parametrized solutions may be transcendental,like modular function.
May 30, 2013 at 18:12 comment added Dietrich Burde Do you mean parametrized solutions $(x(t),y(t),z(t)$ of a Diophantine equation F(x,y,z)=0$ ?
May 30, 2013 at 15:00 comment added Charles Matthews So we have x, f(x), g(x), h(x) ... where f, g, h are certain functions. What now? Which equations are concerned? I have a feeling you want something about implicit algebraic functions.
May 30, 2013 at 14:35 comment added François Brunault I don't understand your question. Could you clarify?
May 30, 2013 at 14:29 comment added quim If each variable can be written as a rational function of x, then the curve has genus zero. If not, then what does "every other variable has function of x the variable as it's solution" mean?
May 30, 2013 at 13:27 comment added XL _At_Here_There @Charles,I think there must be some misunderstanding,I think I am not asking about question of curves of genus 0.maybe some of them are about curves of genus 0.The example is just a very special case.
May 30, 2013 at 13:23 history edited XL _At_Here_There CC BY-SA 3.0
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May 30, 2013 at 13:05 comment added XL _At_Here_There @François,thank you very much for your edit
May 30, 2013 at 12:42 comment added Charles Matthews The question really isn't well posed. The theory of diophantine equations for all curves of genus 0 (i.e. all "space curves" that are rational curves from a geometric point of view) was written down by Hilbert and Hurwitz. It is in Mordell's books. If that is not essentially the question you are asking, I'm not really understanding the question.
May 30, 2013 at 11:19 history edited François G. Dorais
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May 30, 2013 at 11:16 history edited XL _At_Here_There
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May 30, 2013 at 11:08 history asked XL _At_Here_There CC BY-SA 3.0