Timeline for Reference (or proof) for the following identity in Linear Algebra
Current License: CC BY-SA 3.0
16 events
| when toggle format | what | by | license | comment | |
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| May 28, 2013 at 19:42 | comment | added | Yao Hong Kok | It is related to my research (although in engineering) and I just want to make my result mathematically rigorous. I don't see how such a question is off-topic. | |
| May 28, 2013 at 19:32 | vote | accept | Yao Hong Kok | ||
| May 28, 2013 at 19:16 | history | edited | Yao Hong Kok | CC BY-SA 3.0 |
edited body
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| May 28, 2013 at 19:09 | vote | accept | Yao Hong Kok | ||
| May 28, 2013 at 19:27 | |||||
| May 28, 2013 at 18:02 | comment | added | Benoît Kloeckner | This question seems clearly to be off-topic in MO. | |
| May 28, 2013 at 17:06 | answer | added | Andreas Blass | timeline score: 5 | |
| May 28, 2013 at 16:57 | comment | added | Per Alexandersson | If the columns of B are independent of the columns of A, then your identity holds. (Assuming that "independent" in this context means that only the zero vector is the common vector in the spaces the images of the individual matrices span.) You don't really need to find a reference for this, since this is basic linear algebra. | |
| May 28, 2013 at 15:54 | history | edited | Allen Knutson | CC BY-SA 3.0 |
added 3 characters in body
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| May 28, 2013 at 15:53 | comment | added | Allen Knutson | I think by $[A,B]$ he means what I would call $[A B]$, where the two matrices (of the same height $n$) are placed side by side. To the OP: everybody else uses $[A,B]$ to mean AB-BA, so I'm changing your writeup. | |
| May 28, 2013 at 15:06 | answer | added | Felix Goldberg | timeline score: 0 | |
| May 28, 2013 at 14:55 | comment | added | Yao Hong Kok | Sorry, I was typing too quickly and made a few mistakes. I have changed them approriately. Let me do a few more edits to get things right. | |
| May 28, 2013 at 14:53 | comment | added | Simon Wadsley | Surely $[A,B]$ doesn't makes sense unless $p=m=n$? | |
| May 28, 2013 at 14:52 | comment | added | Steve Huntsman | Let $A = 0$ and $B \not = 0$ to see a counterexample. | |
| May 28, 2013 at 14:52 | history | edited | Yao Hong Kok | CC BY-SA 3.0 |
edited body; added 16 characters in body; added 30 characters in body
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| May 28, 2013 at 14:48 | comment | added | john | what is the identity? I don't see any identity in your question. | |
| May 28, 2013 at 14:47 | history | asked | Yao Hong Kok | CC BY-SA 3.0 |