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May 25, 2013 at 19:36 vote accept Fantastic
May 25, 2013 at 19:36 vote accept Fantastic
May 25, 2013 at 19:36
May 24, 2013 at 2:14 comment added Fantastic Thanks a lot David! Your method is amazing! For the lower bound, we may simply replace each of the $N!$ terms by the least one, which has value $2^N/N!$. But it seems your method can be improved further. Thanks again!
May 24, 2013 at 1:44 vote accept Fantastic
May 25, 2013 at 19:36
May 24, 2013 at 1:19 history edited David E Speyer CC BY-SA 3.0
added 659 characters in body
May 23, 2013 at 22:31 history answered David E Speyer CC BY-SA 3.0