Timeline for On the associated graded ring to a section ring
Current License: CC BY-SA 3.0
4 events
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| May 24, 2013 at 14:28 | comment | added | Chuck Hague | That makes sense, although it's not clear to me why the multiplication map $ R_1(\mathcal L)^{\otimes m} \to R_m(\mathcal L)$ should be surjective (but I might be missing something easy here). | |
| May 24, 2013 at 3:40 | comment | added | Allen Knutson | I think all that's happening here is that you're filtering your $R$ by powers of an ideal $I$. No? In which case $R$ is Noetherian so $gr_I\ R$ is too. | |
| May 23, 2013 at 20:21 | history | edited | Chuck Hague | CC BY-SA 3.0 |
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| May 23, 2013 at 19:42 | history | asked | Chuck Hague | CC BY-SA 3.0 |