Timeline for Can group solvability be detected from identities among the generators?
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| May 22, 2013 at 17:01 | comment | added | Matt Brin | I now understand my confusion and my second error. Gerry is right since he interpreted my notation literally and I did not. In [X,X], I erred in letting the elements run over X and also the inverses of elements in X. | |
| May 22, 2013 at 8:04 | comment | added | user6976 | @Alireza: Isn't it what Matt wrote in his comment to Gerry's answer. I think the only non-clear remaining part of the question is whether $X_2=1$ implies $G_m=1$ for some $m$. | |
| May 21, 2013 at 13:28 | history | answered | Alireza Abdollahi | CC BY-SA 3.0 |