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José Hdz. Stgo.
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You can define $Ext^n$$\mathrm{Ext}^n$ as the set of isomorphism classes of $n$-step extensions, equipped with the Baer sum. This eliminates choices from the definition of $Ext$$\mathrm{Ext}$ in exactly the same spirit as your original post eliminates choices from the definition of the trace.

You can define $Ext^n$ as the set of isomorphism classes of $n$-step extensions, equipped with the Baer sum. This eliminates choices from the definition of $Ext$ in exactly the same spirit as your original post eliminates choices from the definition of the trace.

You can define $\mathrm{Ext}^n$ as the set of isomorphism classes of $n$-step extensions, equipped with the Baer sum. This eliminates choices from the definition of $\mathrm{Ext}$ in exactly the same spirit as your original post eliminates choices from the definition of the trace.

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Steven Landsburg
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You can define $Ext^n$ as the set of isomorphism classes of $n$-step extensions, equipped with the Baer sum. This eliminates choices from the definition of $Ext$ in exactly the same spirit as your original post eliminates chocieschoices from the definition of the trace.

You can define $Ext^n$ as the set of isomorphism classes of $n$-step extensions, equipped with the Baer sum. This eliminates choices from the definition of $Ext$ in exactly the same spirit as your original post eliminates chocies from the definition of the trace.

You can define $Ext^n$ as the set of isomorphism classes of $n$-step extensions, equipped with the Baer sum. This eliminates choices from the definition of $Ext$ in exactly the same spirit as your original post eliminates choices from the definition of the trace.

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Steven Landsburg
  • 23k
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  • 95
  • 153

You can define $Ext^n$ as the set of isomorphism classes of $n$-step extensions, equipped with the Baer sum. This eliminates choices from the definition of $Ext$ in exactly the same spirit as your original post eliminates chocies from the definition of the trace.