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May 21, 2013 at 6:11 comment added Qijun Yan Yes, here by "connected" I mean $G$ is connected topologically. I can assume that $G/S$ has constant rank.
May 21, 2013 at 6:10 vote accept Qijun Yan
May 21, 2013 at 5:46 comment added Laurent Moret-Bailly OK if "connected" means "with connected fibers". But I suspect the OP means "connected" literally.
May 20, 2013 at 16:17 history edited Keenan Kidwell CC BY-SA 3.0
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May 20, 2013 at 16:11 history edited Keenan Kidwell CC BY-SA 3.0
added 2 characters in body; added 233 characters in body; added 31 characters in body; deleted 148 characters in body
May 20, 2013 at 16:08 history undeleted Keenan Kidwell
May 20, 2013 at 16:05 history deleted Keenan Kidwell
May 20, 2013 at 16:04 history answered Keenan Kidwell CC BY-SA 3.0