Skip to main content
5 events
when toggle format what by license comment
May 19, 2013 at 12:44 comment added Nevermind So what you say is,that different choices of $r$ gives different vector fields on $M$? Hmm... Can you explain why?
May 19, 2013 at 12:32 comment added Nevermind Ok it requires both the data of $f$ and $r$ and $r$ is not uniquely defined by $f$. But it is a well defined vector field on $M$ at least. Right?
May 19, 2013 at 11:51 history edited Lev Soukhanov CC BY-SA 3.0
added 12 characters in body
May 19, 2013 at 11:46 comment added Benoît Kloeckner In other word, your "pull-back" vector field depends on both $f$ and $r$, while to properly define a $f^*X$ you would like it to depend only on $f$.
May 19, 2013 at 11:39 history answered Lev Soukhanov CC BY-SA 3.0