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Hi,

I have a matrix of the form:
A=VDV^H $A=VDV^H$, where V$V$ is a M times 2M$M \times 2M$ complex matrix, D$D$ is a 2M times 2M$2M \times 2M$ diagonal real matrix, thus the dimension of A$A$ is M times M$M \times M$.

My problem is how to maximize the determinant of A be choose the$A$ by choosing the digonal of Ddiagonal $D$ (suppose the sum of diagonals of D$D$ equals to 1$1$)?

Since the dimension of V$V$ is M \times 2M$M \times 2M$, I don't know how to slovesolve this problem. Thanks.

Hi,

I have a matrix of the form:
A=VDV^H, where V is a M times 2M complex matrix, D is a 2M times 2M diagonal real matrix, thus the dimension of A is M times M.

My problem is how to maximize the determinant of A be choose the the digonal of D (suppose the sum of diagonals of D equals to 1)?

Since the dimension of V is M \times 2M, I don't know how to slove this problem. Thanks.

Hi,

I have a matrix of the form $A=VDV^H$, where $V$ is a $M \times 2M$ complex matrix, $D$ is a $2M \times 2M$ diagonal real matrix, thus the dimension of $A$ is $M \times M$.

My problem is how to maximize the determinant of $A$ by choosing the diagonal $D$ (suppose the sum of diagonals of $D$ equals to $1$)?

Since the dimension of $V$ is $M \times 2M$, I don't know how to solve this problem. Thanks.

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How to maximize the determinant of a matrix of the form VDV^H

Hi,

I have a matrix of the form:
A=VDV^H, where V is a M times 2M complex matrix, D is a 2M times 2M diagonal real matrix, thus the dimension of A is M times M.

My problem is how to maximize the determinant of A be choose the the digonal of D (suppose the sum of diagonals of D equals to 1)?

Since the dimension of V is M \times 2M, I don't know how to slove this problem. Thanks.