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Nov 19, 2013 at 15:39 comment added Will Todd is right on both counts.
Jul 13, 2013 at 20:30 comment added Todd Trimble GH, I think you misunderstood; the text before the note is not an asserted proposition, it's a condition on $(f, g)$ that the OP wishes to consider. (Surely this could have been stated more clearly though.)
Jul 13, 2013 at 18:28 comment added GH from MO Your initial statement is false. For example, if $f(x)=|x|$ and $g(x)=x+1$, then $f(x)=f(y)$ but $f(g(x))\neq f(g(y))$ for $x=1$ and $y=-1$.
Jun 13, 2013 at 16:45 answer added Gerhard Paseman timeline score: 2
May 16, 2013 at 12:55 answer added Paul Taylor timeline score: 3
May 16, 2013 at 12:32 history asked Will CC BY-SA 3.0