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May 15, 2013 at 8:23 history edited John Terry CC BY-SA 3.0
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May 15, 2013 at 7:19 comment added Mariano Suárez-Álvarez @John, as soon as you get 50 points of reputation you will be able to add comments. Using the answer box to respond to someone's answer does not work at all.
May 15, 2013 at 7:03 comment added Geoff Robinson I corrected my post- I was thinking about the exponent $p$ case. The other direction is OK, as I explained, because the whole of ${\rm Sp}(2r,p)$ is induced by the action of ${\rm SL}(V)$ since the representation does extend to the appropriate central extension of $H,$ which has a subgroup $Z(G) \times {\rm Sp}(2r,p).$
May 15, 2013 at 6:36 history answered John Terry CC BY-SA 3.0