Timeline for Can an accumulation point be an eigenvalue?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| May 14, 2013 at 18:57 | comment | added | Pietro Majer | Just think of diagonal operators on $l_2$, to get any sequence accumulating to 0 as spectrum, 0 being an eigenvalue or not. | |
| May 14, 2013 at 14:58 | answer | added | Harm Derksen | timeline score: 2 | |
| May 14, 2013 at 14:18 | comment | added | Gerald Edgar | $0$ is always in the spectrum (for a compact operator on an infinite-dimensional Hilbert space). For some such operators $0$ is an eigenvalue, but for others it is not. | |
| May 14, 2013 at 13:11 | comment | added | The User | This is true in every infinite dimensional Hilbert space. The spectrum is always closed, thus every accumulation point of the spectrum is an element of the spectrum. | |
| May 14, 2013 at 13:10 | history | edited | Federico Poloni | CC BY-SA 3.0 |
deleted 20 characters in body
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| May 14, 2013 at 13:06 | history | asked | user33960 | CC BY-SA 3.0 |