Timeline for Principal value of integral
Current License: CC BY-SA 3.0
14 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 17, 2013 at 6:49 | answer | added | Zurab Silagadze | timeline score: 0 | |
| S May 15, 2013 at 11:00 | vote | accept | Mark | ||
| May 15, 2013 at 11:00 | vote | accept | Mark | ||
| S May 15, 2013 at 11:00 | |||||
| May 14, 2013 at 19:37 | vote | accept | Mark | ||
| May 15, 2013 at 11:00 | |||||
| May 14, 2013 at 16:42 | answer | added | Gerald Edgar | timeline score: 5 | |
| May 14, 2013 at 14:28 | comment | added | Carlo Beenakker | @Gerald: it is equivalent to the textbook definition ${\cal P}\int_a^b dx f(x)=\frac{1}{2} \lim_{\epsilon\rightarrow 0}\left(\int_{a-i\epsilon}^{b-i\epsilon} dx f(x)+ \int_{a+i\epsilon}^{b+i\epsilon} dx f(x)\right)$ | |
| May 14, 2013 at 14:22 | comment | added | Gerald Edgar | @Carlo: that is perhaps a sensible definition. Can you cite a textbook that uses that definition? | |
| May 14, 2013 at 14:04 | answer | added | Carlo Beenakker | timeline score: 4 | |
| May 14, 2013 at 13:59 | comment | added | user25199 | Numerically I find 1.57 - suspiciously close to $\pi/2$. | |
| May 14, 2013 at 13:12 | comment | added | Carlo Beenakker | I would presume each pole at $x_n=n\pi$ is excluded in an interval $(x_n-\epsilon,x_n+\epsilon)$, and then the limit $\epsilon\rightarrow 0$ is taken. | |
| May 14, 2013 at 12:18 | comment | added | Gerald Edgar | Since there are multiple poles, I do not know what "principal value" means. Perhaps you can provide a definition? | |
| May 14, 2013 at 7:52 | comment | added | Mark | @user11000: math.stackexchange.com/questions/384291/… | |
| May 14, 2013 at 7:44 | comment | added | user11000 | @Mark: Could you link the corresponding math.stackexchange post? Thanks. | |
| May 14, 2013 at 6:46 | history | asked | Mark | CC BY-SA 3.0 |