Skip to main content
10 events
when toggle format what by license comment
May 11, 2013 at 14:56 answer added user9072 timeline score: 7
May 11, 2013 at 14:54 answer added Mike Bennett timeline score: 5
May 11, 2013 at 4:57 comment added Gerhard Paseman Wlod: yes, for the problem as written, your form is appropriate. If one is looking for common differences between powers, 3^a - 2^c = 2^d - 3^b leads to a nice mod 8 restriction. I haven't taken it farther. Gerhard "Fast And Correct: Choose One" Paseman, 2013.05.10
May 11, 2013 at 3:26 comment added Włodzimierz Holsztyński @Piotr: for starters, you may check on pretty old papers where they got results about integers $n\cdot(n+1)$, and $n\cdot(n+2)$, etc. (not too much of that "etc.") which decompose into the product of a few first primes only. These problems are different but at least they can be viewed as relatives.
May 11, 2013 at 3:20 comment added Włodzimierz Holsztyński @Gerhard "lightning fast" Paseman: Oooops, I was too slow, or the opposite, too fast.
May 11, 2013 at 3:17 comment added Włodzimierz Holsztyński @Piotr: about the trivial solutions, isn't it simpler to forget them by assuming that both exponents $a\ b$ are greater than $1$? (Otherwise there are more trivial "solutions").
May 11, 2013 at 3:13 comment added Włodzimierz Holsztyński @Gerhard "positive tropism" Paseman: do you mean $3^a-3^b=2^c-2^d$ ?
May 11, 2013 at 3:10 comment added Gerhard Paseman Oops. Sign Error. Even so, trying the appropriate formulation with powers of 3 on one side and powers of 2 on the other side might appear in the literature. Gerhard "Let's Take Absolute Values Instead" Paseman, 2013.05.10
May 11, 2013 at 3:02 comment added Gerhard Paseman You might find it revealing to study the system 3^a + 3^b = 2^c + 2^d. That will show some constraints on the possiblities and likely answer some of your questions above. Gerhard "Ask Me About Elementary Analysis" Paseman, 2013.05.10
May 11, 2013 at 2:41 history asked Piotr Shatalin CC BY-SA 3.0