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Timeline for probability calculation

Current License: CC BY-SA 3.0

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May 15, 2013 at 21:29 comment added anonymous Why did you ignore the part $\sum_{k=\lfloor (e-1)/2\rfloor}^{\min(b,e)}\frac{{e \choose k}{me-e \choose b-k}}{{me \choose b}}$?
May 10, 2013 at 16:25 comment added meij This recursion is more efficient than the one I used.
May 10, 2013 at 8:57 history edited Roland Bacher CC BY-SA 3.0
added 20 characters in body
May 10, 2013 at 8:48 history answered Roland Bacher CC BY-SA 3.0