Timeline for Proof that the Hodge-de Rham Rank Equals the Euler Characteristic
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| May 9, 2013 at 19:18 | comment | added | Liviu Nicolaescu | Check section 2.1.4 at this link www3.nd.edu/~lnicolae/ind-thm.pdf These are notes for a graduate course on index theory that I've just taught this semester. Section2.1.4 is about Hodge theory and deals precisely with your question. | |
| May 9, 2013 at 17:36 | history | edited | Donu Arapura | CC BY-SA 3.0 |
added 342 characters in body
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| May 9, 2013 at 14:17 | comment | added | user33845 | P.S. By index of an operator $A$ I mean dim of the image of $A$ minus the dim of the cokernel of $A$. | |
| May 9, 2013 at 14:16 | comment | added | user33845 | . . . so how does one get from the Hodge decomposition to index equaling the Euler characteristic? | |
| May 9, 2013 at 14:00 | history | answered | Donu Arapura | CC BY-SA 3.0 |