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May 9, 2013 at 17:34 answer added David E Speyer timeline score: 4
May 9, 2013 at 16:11 vote accept David E Speyer
May 9, 2013 at 17:01
May 9, 2013 at 15:52 answer added Will Sawin timeline score: 4
May 9, 2013 at 4:53 comment added Will Sawin If we add extra variables, $X$ can always be seen as the intersection of a subtorus and a subvariety cut out by linear equations. If it is a complete intersection when so described, I think we can wedge with a form that is perpendicular to the subtorus to reduce to the linear equations case, but that might be nonsense.
May 9, 2013 at 1:42 comment added Allen Knutson This is a sort of Hodge theorem for subvarieties of tori, I guess? That each cohomology class should have but one representative of this form?
May 9, 2013 at 1:34 history edited Allen Knutson CC BY-SA 3.0
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May 9, 2013 at 0:05 history edited David E Speyer CC BY-SA 3.0
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May 8, 2013 at 23:37 history asked David E Speyer CC BY-SA 3.0