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May 7, 2013 at 20:57 comment added Gerhard Paseman Tom, I've seen postings by a Butch Malahide on other fora, which may help you get in touch with him/her/it. In this day and age, referring to MathOverflow users by number should be socially acceptable. Gerhard "User 3528. Aliases 3206, 3371..." Paseman, 2013.05.07
May 7, 2013 at 19:32 comment added Tom Leinster PS to Butch: I'll acknowledge you when I update the paper for which I needed this, arxiv.org/abs/1209.3606. Forgive the impertinence, but is Butch Malahide your real name? Feel free to contact me by email. (I'd contact you myself, but there's no address on your profile.)
May 7, 2013 at 19:29 comment added Tom Leinster Excellent. Thanks very much. For the sake of precision, let me add that they don't quite do the case $n=3$ in the sense described in my question. They do show that if a set $\mathcal{U}$ of subsets of $X$ satisfies the partition condition for all $n\leq 3$, then $\mathcal{U}$ is an ultrafilter. But they seem not to observe that it suffices to require it for $n=3$ (which implies it for $n=0,1,2$). Quite possibly they knew it but just didn't think it was worth mentioning.
May 7, 2013 at 19:25 vote accept Tom Leinster
May 7, 2013 at 18:56 history edited user33772 CC BY-SA 3.0
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May 7, 2013 at 7:34 history edited user33772 CC BY-SA 3.0
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May 7, 2013 at 7:27 comment added Gerhard Paseman Welcome to MathOverflow! Gerhard "Ask Me About System Design" Paseman, 2013.05.07
May 7, 2013 at 7:06 history answered user33772 CC BY-SA 3.0