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May 10, 2013 at 12:01 comment added Sergei Ivanov @alex: I think you are right. This simplification did not occur to me.
May 10, 2013 at 10:07 comment added alex Thank you! This was very helpful. Maybe I'm missing something here, but couldn't you apply the same argument for $f(x)^n$ without using the Hausdorff distance result to drop the power, and get that $$\int_{S^{n-1}} |f(x)^n - r_0| dx \leq \epsilon$$ ? This would give a constant independent of the dimension.
May 7, 2013 at 17:44 vote accept alex
May 6, 2013 at 20:14 history edited Sergei Ivanov CC BY-SA 3.0
added an estimate of the Nikodym distance
May 6, 2013 at 18:35 history answered Sergei Ivanov CC BY-SA 3.0