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May 8, 2013 at 22:22 vote accept user27318
May 4, 2013 at 21:09 comment added Joe Silverman @Asaf: Aren't real quadratic fields the 1-dimensional case? So your comments are probably more relevant to, say, a totally real cubic field.
May 4, 2013 at 21:07 answer added Joe Silverman timeline score: 2
May 4, 2013 at 18:37 comment added Asaf Think about this in the 2-dim case (say real quad. fields). The "short" basis will be basically consists of the first and second shortest vectors. The "bound" your asking is for how high the point representing this lattice goes to the cusp in the homogeneous space PSL2(R)/PSL2(Z). As can be seen by the basic theory of quad. forms, you can get forms of very large discriminant which will result at point very high up in the cusp (that means the shortest vector is very short, hence in the 2-dim case, the second one is very long). In general I think you might get something from Baker's inequality.
May 4, 2013 at 18:00 history asked user27318 CC BY-SA 3.0