Timeline for Which matrix/operator in a cone has the largest negative spectral part?
Current License: CC BY-SA 3.0
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| Mar 6, 2014 at 14:53 | comment | added | Suvrit | You wrote about: $K$ is the set of symmetric matrices, in which case this is fine. If $K$ is a closed convex cone such as nonengative orthant or psd matrices, then $A_- = 0$ for all matrices, so I guess I'm confused about your terminology a bit... | |
| Mar 6, 2014 at 7:07 | comment | added | Felix Goldberg | @Suvrit But if $A_{+}=0$ then $A$ could land outside $\mathcal{K}$. | |
| Mar 6, 2014 at 2:55 | comment | added | Suvrit | you mean "maximizes m(A)" right? isn't this maximized by a matrix for which $A_+=0$, then $m(A)=1$. | |
| Mar 6, 2014 at 2:23 | history | edited | Felix Goldberg | CC BY-SA 3.0 |
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| May 4, 2013 at 12:36 | history | edited | Felix Goldberg | CC BY-SA 3.0 |
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| May 4, 2013 at 10:27 | history | edited | Felix Goldberg | CC BY-SA 3.0 |
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| May 4, 2013 at 7:21 | history | edited | Felix Goldberg |
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| May 4, 2013 at 7:13 | history | asked | Felix Goldberg | CC BY-SA 3.0 |