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May 1, 2013 at 19:18 answer added Jim Humphreys timeline score: 5
Apr 30, 2013 at 22:58 comment added Arkandias Thank you nosr. If you could post your answer so I can accept it.
Apr 30, 2013 at 17:09 comment added Marc Palm nosr. please put this as answer.
Apr 30, 2013 at 15:37 comment added user28172 [I assume when you wrote "maximal (split) torus" you mean that $T$ is a split maximal $E$-torus of $G$ that is also maximal as an $E$-torus.]
Apr 30, 2013 at 15:35 comment added user28172 They're equal. This can be seen in multiple ways. For example, the evident isomorphism $S'_E \rightarrow T$ induced by $G_{E'} \twoheadrightarrow G$ gives an identification ${\rm{X}}_F(S') = {\rm{X}}_F(T)$ under which $\Phi(G',S')$ is carried isomorphically onto $\Phi(G,T)$ (using the equality of $\mathfrak{g}'$ with the underlying $F$-vector space of $\mathfrak{g}$ to match root spaces), and the Weyl group of this common root system is naturally identified with the finite constant groups $W$ and $W'$. This respects the induced map $W'_E \rightarrow W$, so the latter is an isomorphism.
Apr 30, 2013 at 14:35 history asked Arkandias CC BY-SA 3.0