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Apr 30, 2013 at 19:00 answer added Peter Michor timeline score: 0
Apr 30, 2013 at 13:11 comment added Zeyu Oops. Thanks for pointing it out. Fixed.
Apr 30, 2013 at 13:09 history edited Zeyu CC BY-SA 3.0
added 3 characters in body
Apr 30, 2013 at 12:39 comment added Andreas Blass You wrote "ker$(A)\supsetneq V$, that is, $Ax=0$ admitting a solution not in $V$." These are not equivalent; did you mean ker$(A)\not\subseteq V$? Or did you really intend that the kernel should include all of $V$?
Apr 30, 2013 at 12:37 answer added Liviu Nicolaescu timeline score: 1
Apr 30, 2013 at 12:30 history edited José Hdz. Stgo. CC BY-SA 3.0
edited title
Apr 30, 2013 at 12:09 history asked Zeyu CC BY-SA 3.0