Timeline for Inequivalence of group representations preserved under tensor product?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Apr 27, 2013 at 3:43 | comment | added | Venkataramana | I mean the following; suppose $F$ is a finite group for which Richard Stanley's example works. Suppose $G$ is a Lie group whose connected component group $G/G^0$ is $F$. Then for $G$ also, there exist two reps $r_1,r_2$ as above. | |
| Apr 26, 2013 at 18:29 | comment | added | Yemon Choi | See my comment above. I think the difference is finiteness, but perhaps I have made an error | |
| Apr 26, 2013 at 10:57 | comment | added | Venkataramana | I would say the difference comes from the connectedness or otherwise of the group. If $G$ is not conected, then the group of connected components may well be of the type given by Richard Stanley. | |
| Apr 25, 2013 at 20:12 | history | edited | Venkataramana | CC BY-SA 3.0 |
added the assumption that $r_1,r_2$ are irreducible.
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| Apr 25, 2013 at 18:41 | vote | accept | Matt Hastings | ||
| Apr 25, 2013 at 18:41 | comment | added | Matt Hastings | Thanks! So it seems the question has a simple answer in both the finite and Lie cases, but the answer is very different in these two cases. | |
| Apr 25, 2013 at 18:23 | history | answered | Venkataramana | CC BY-SA 3.0 |