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Mar 26, 2016 at 13:33 history edited Lee Mosher CC BY-SA 3.0
added 97 characters in body
Mar 26, 2016 at 13:32 comment added Lee Mosher Oops, that's a good catch in an old answer. Thanks.
Mar 26, 2016 at 6:48 comment added dvitek For your example, do you mean $H(x,t) = x^3 - tx$ at time $t = 0$? I'm pretty sure the critical points of $x^2-t$ don't change with $t$, but it's certainly possible I'm not understanding what $H$ is supposed to be.
Apr 25, 2013 at 19:18 vote accept Andrew
Apr 25, 2013 at 13:38 history answered Lee Mosher CC BY-SA 3.0