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Apr 22, 2013 at 12:01 comment added Max You are right. this is a minimal injective resolution.
Apr 22, 2013 at 3:26 comment added Hailong Dao Mohan, I think the question is about an injective resolution. Anyway, voted to close as this is not a real question.
Apr 22, 2013 at 2:50 answer added Youngsu timeline score: 1
Apr 21, 2013 at 14:30 comment added Mohan What are the $I$'s? I assume your sequence above is exact. With no conditions, this is not true. For example take $d=1$, with $0\to R\to I_0\to k$ split exact where $k$ is the residue field.
Apr 21, 2013 at 8:29 history asked Max CC BY-SA 3.0