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Apr 4, 2016 at 13:07 answer added Simon Henry timeline score: 9
Apr 21, 2013 at 0:22 comment added Colin McLarty I'll just add that Grothendieck probably thought of this as analogous to saying a topology on a set $S$ always has $S$ itself as an open subset.
Apr 19, 2013 at 14:49 comment added Zhen Lin You can make do with much less than a Grothendieck pretopology: all you need to have a good notion of sheaf (i.e. one that generates a topos) is a coverage. See here: ncatlab.org/nlab/show/coverage
Apr 19, 2013 at 12:31 history asked Nicolás CC BY-SA 3.0