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Allen Knutson
Allen Knutson
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I am tempted to answer your question by the negative:
I believe that there does not exist any other, simpler, way of saying "left-invariant pseudo-differential operator on $G$".

The reason is that if you look at the subset of smoohtingsmoothing operators (operators with smooth integral kernel), I already don't know how to say "left-invariant smoothing operator on $G$" in any simpler (algebraic) way.

I am tempted to answer your question by the negative:
I believe that there does not exist any other, simpler, way of saying "left-invariant pseudo-differential operator on $G$".

The reason is that if you look at the subset of smoohting operators (operators with smooth integral kernel), I already don't know how to say "left-invariant smoothing operator on $G$" in any simpler (algebraic) way.

I am tempted to answer your question by the negative:
I believe that there does not exist any other, simpler, way of saying "left-invariant pseudo-differential operator on $G$".

The reason is that if you look at the subset of smoothing operators (operators with smooth integral kernel), I already don't know how to say "left-invariant smoothing operator on $G$" in any simpler (algebraic) way.

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André Henriques
André Henriques
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I am tempted to answer your question by the negative:
I believe that there does not exist any other, simpler, way of saying "left-invariant pseudo-differential operator on $G$".

The reason is that if you look at the subset of smoohting operators (operators with smooth integral kernel), I already don't know how to say "left-invariant smoothing operator on $G$" in any simpler (algebraic) way.