Timeline for General criterion for homomorphism between Clifford Algebras
Current License: CC BY-SA 3.0
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| Apr 18, 2013 at 16:37 | history | edited | MTS | CC BY-SA 3.0 |
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| Apr 18, 2013 at 16:35 | comment | added | darij grinberg | The universal property doesn't give you a good way to check whether a given map is an algebra homomorphism (unless it's constructed using the property to begin with). | |
| Apr 18, 2013 at 16:34 | comment | added | darij grinberg | All algebra homomorphisms arise this way, not only when $A$ itself is Clifford, but generally. This is simply because you can restrict any algebra homomorphism from $\mathrm{Cl}(V)$ to $V$, and then the universal property (in which you have forgotten the word "unique") yields that the extension of this restriction to $\mathrm{Cl}(V)$ is your original algebra homomorphism. | |
| Apr 18, 2013 at 16:21 | history | asked | Clark Chong | CC BY-SA 3.0 |