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Jul 19, 2022 at 13:14 history edited YCor CC BY-SA 4.0
formatting, changed tag
Apr 27, 2013 at 21:57 answer added Bill Lawvere timeline score: 21
Apr 22, 2013 at 14:55 answer added Ronnie Brown timeline score: 10
Apr 20, 2013 at 9:38 vote accept Amr
Apr 20, 2013 at 9:38 vote accept Amr
Apr 20, 2013 at 9:38
Apr 19, 2013 at 14:36 comment added Marcos Cossarini For the non-Hausdorff case, see ncatlab.org/nlab/show/exponential+law+for+spaces.
Apr 18, 2013 at 21:21 history edited Paul Taylor
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Apr 18, 2013 at 9:44 history edited Amr CC BY-SA 3.0
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Apr 18, 2013 at 9:43 comment added Amr @johnodoe Yes. I will fix this now
Apr 18, 2013 at 6:11 answer added johndoe timeline score: 5
Apr 18, 2013 at 5:53 comment added johndoe @Amr: it seems you misplaced some * in the edited version
Apr 17, 2013 at 21:51 history edited Amr CC BY-SA 3.0
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Apr 17, 2013 at 21:43 comment added Amr @Anton Fetisov I mean the interval [0,1]. I also don't think that this case is useless. I will add a motivation to my question.
Apr 17, 2013 at 17:03 comment added johndoe to Anton Fetisov: why is the case I rather useless?
Apr 17, 2013 at 15:55 answer added Daniel Barter timeline score: 1
Apr 17, 2013 at 14:20 answer added Paul Taylor timeline score: 25
Apr 17, 2013 at 13:25 answer added Fernando timeline score: 4
Apr 17, 2013 at 13:04 comment added Anton Fetisov If $\mathbb{I}$ denotes $[0,1]$, then I don't know the answer, but this case is rather useless. For $\mathbb{I}$ a general topological space, the answer is no. Such topology can be given iff $X$ is locally compact. If you are fine with smaller subcategory of $\mathcal{T}op$, then there is a classical solution: work in a category of compactly generated hausdorff spaces and equip $Hom(X,Y)$ with compact-open topology.
Apr 17, 2013 at 12:31 history asked Amr CC BY-SA 3.0