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Apr 13, 2017 at 12:19 history edited CommunityBot
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Apr 17, 2013 at 13:51 comment added inkspot I get the impression that the OP writes "orbifold" to mean "geometric quotient of an orbifold". That is, a variety rather than a stack. In any case, it is true that every 2-dimensional quotient singularity is smoothable, because every 2-dimensional rational singularity is smoothable. See, for example, Artin's "An algebraic construction of Brieskorn's resolutions".
Apr 17, 2013 at 10:46 comment added naf You might find the paper by Schlessinger, "Rigidity of quotient singularities." Invent. Math. 14 (1971), 17–26 useful. In particular, it should explain the phenomenon described in your last paragraph.
Apr 17, 2013 at 9:44 comment added Rhys Davies I'm just interested in deformations of these as varieties, so I'm not sure what you mean by 'deform the group action'. In the du Val examples, the smoothed varieties are not orbit spaces.
Apr 17, 2013 at 9:25 comment added Peter Michor How do you deform the group action? the members of your flat family again orbit spaces?
Apr 17, 2013 at 8:54 history asked Rhys Davies CC BY-SA 3.0